[gradsusr] Wind-chill parameter GrADS -
L.B.
bcbass2989 at gmail.com
Mon Feb 24 12:52:08 EST 2014
Leopoldo,
Based on the first link you mentioned, that formula looks similar to the
old windchill formula. The newer one which you used in your two
calculations are correct. I should mention that the windchill formula is
meant for temperatures of 50F(10C) or less. This is the reason why your
windchill values are only slightly lower than your actual temperature
values.
*William (L.B.) LaForce*
Meteorologist
Central Michigan University '13
www.tornadoinsanity.com
On Mon, Feb 24, 2014 at 8:43 AM, Leopoldo Alvarez <lap.bolsa at gmail.com>wrote:
> Hi Willians,
>
> Look at this webpage->
> http://www.lenntech.com/calculators/wind/wind-chill.htm
> 30 km/h (wind)
> 18ºC (temperature)
> 12.1ºC (windchill)
>
> - - - - - - - - - - -
>
> In our examples ....
> I use your formulation...
> - [1] I use your formulation corrected (convert KPH to MPH and K to F to
> input into the equation)
>
> 'far=((9/5)*t)-459.67'
> 'mph=tg1*2.236936'
> 'define chill =
> 35.74+0.6215*far-35.75*pow(mph,0.16)+0.4275*far*pow(mph,0.16)'
> 'chill2=(chill-32)/1.8'
> 'd chill2'
>
> Date / wind (MPH) / temp (ºF) / windchill (ºF)
> 2014-FEB-19-13Z 17.1496 66.0072 64.8952
> 2014-FEB-19-14Z 19.4474 66.7105 65.5746
> 2014-FEB-19-15Z 19.4474 66.2803 65.0114
>
>
> - [2] This is the other proposal that you have shown me ...
>
> 'define chill =
> 13.12+0.6215*(t-273.15)-11.37*pow((tg1*3.6),0.16)+0.3965*(t-273.15)*pow((tg1*3.6),0.16)'
>
> Date / wind (KPH) / temp (ºC) / windchill (ºC)
> 2014-FEB-19-13Z 27.5996 18.8929 18.2662
> 2014-FEB-19-14Z 31.2976 19.2836 18.6438
> 2014-FEB-19-15Z 31.2976 19.0446 18.3308
>
> I still think that with a wind of 30 km/h and a temperature of 18.8 °C,
> the windchill can not be a 'lower tenths'..
> I'm confused, and I have no security ...
> http://www.easysurf.cc/cnver16.htm
> http://es.easycalculation.com/weather/wind-chill.php
>
> Best,
>
> Leopoldo Alvarez
>
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