[gradsusr] Wind-chill parameter GrADS -

[Leopoldo Alvarez]

Hi Willians,

Look at this webpage->
http://www.lenntech.com/calculators/wind/wind-chill.htm
30 km/h (wind)
18ºC (temperature)
12.1ºC (windchill)

- - - - - - - - - - -

In our examples ....
I use your formulation...
- [1] I use your formulation corrected (convert KPH to MPH and K to F to 
input into the equation)

'far=((9/5)*t)-459.67'
'mph=tg1*2.236936'
'define chill = 
35.74+0.6215*far-35.75*pow(mph,0.16)+0.4275*far*pow(mph,0.16)'
'chill2=(chill-32)/1.8'
'd chill2'

  Date / wind (MPH) / temp (ºF) / windchill (ºF)
2014-FEB-19-13Z 17.1496 66.0072 64.8952
2014-FEB-19-14Z 19.4474 66.7105 65.5746
2014-FEB-19-15Z 19.4474 66.2803 65.0114


- [2] This is the other proposal that you have shown me ...

'define chill = 
13.12+0.6215*(t-273.15)-11.37*pow((tg1*3.6),0.16)+0.3965*(t-273.15)*pow((tg1*3.6),0.16)'

  Date / wind (KPH) / temp (ºC) / windchill (ºC)
2014-FEB-19-13Z   27.5996  18.8929  18.2662
2014-FEB-19-14Z   31.2976  19.2836  18.6438
2014-FEB-19-15Z   31.2976  19.0446  18.3308

I still think that with a wind of 30 km/h and a temperature of 18.8 °C, 
the windchill can not be a 'lower tenths'..
I'm confused, and I have no security ...
http://www.easysurf.cc/cnver16.htm
http://es.easycalculation.com/weather/wind-chill.php

Best,

Leopoldo Alvarez
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