<div dir="ltr"><div>Leopoldo,<br><br></div>Based on the first link you mentioned, that formula looks similar to the old windchill formula. The newer one which you used in your two calculations are correct. I should mention that the windchill formula is meant for temperatures of 50F(10C) or less. This is the reason why your windchill values are only slightly lower than your actual temperature values.<br>
</div><div class="gmail_extra"><br clear="all"><div><div dir="ltr"><b>William (L.B.) LaForce</b><div>Meteorologist</div><div>Central Michigan University '13<br></div><div><a href="http://www.tornadoinsanity.com" target="_blank">www.tornadoinsanity.com</a></div>
</div></div>
<br><br><div class="gmail_quote">On Mon, Feb 24, 2014 at 8:43 AM, Leopoldo Alvarez <span dir="ltr"><<a href="mailto:lap.bolsa@gmail.com" target="_blank">lap.bolsa@gmail.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div bgcolor="#FFFFFF" text="#000000">
<font face="Dax">Hi Willians, </font><font face="Dax"><br>
</font><br>
<font face="Dax">
<span lang="en"><span>Look at</span> <span>this
webpage-><br>
</span></span><a href="http://www.lenntech.com/calculators/wind/wind-chill.htm" target="_blank">http://www.lenntech.com/calculators/wind/wind-chill.htm</a><br>
30 km/h (wind)<br>
18ºC (temperature)<br>
12.1ºC (windchill)<br>
<br>
- - - - - - - - - - -<br>
</font><br>
<font face="Dax">
<span lang="en"><span>In our examples</span> <span>....<br>
</span></span>I use your formulation...</font><br>
<font face="Dax">
<span lang="en"><span>- [1] I</span> <span>use</span> your
<span>formulation </span></span></font><font face="Dax"><span lang="en"><span><font face="Dax"><span lang="en"><span>corrected
(convert KPH to MPH and K to F to input into the
equation)</span></span></font></span></span></font><font face="Dax"><span lang="en"><span><font face="Dax"><span lang="en"><span>
</span></span></font></span></span></font><font face="Dax"><span lang="en"><span><font face="Dax"><span lang="en"><span></span> </span></font><br>
<br>
</span></span>'far=((9/5)*t)-459.67'<br>
'mph=tg1*2.236936'<br>
'define chill =
35.74+0.6215*far-35.75*pow(mph,0.16)+0.4275*far*pow(mph,0.16)'<br>
'chill2=(chill-32)/1.8'<br>
'd chill2'<br>
</font><br>
<font face="Dax"> Date / wind (MPH) / temp (ºF) / windchill (ºF)<br>
2014-FEB-19-13Z </font><font face="Dax"><font face="Dax">17.1496
</font> </font><font face="Dax"><font face="Dax">66.0072</font>
</font><font face="Dax"><font face="Dax">64.8952<br>
</font>2014-FEB-19-14Z </font><font face="Dax"><font face="Dax">19.4474</font>
</font><font face="Dax"><font face="Dax">66.7105</font> </font><font face="Dax"><font face="Dax">65.5746<br>
</font>2014-FEB-19-15Z </font><font face="Dax"><font face="Dax">19.4474</font>
</font><font face="Dax"><font face="Dax">66.2803</font> </font><font face="Dax">65.0114</font><br>
<br>
<br>
<font face="Dax">
<span lang="en"><span>- [2]
This is the other</span> <span>proposal</span> <span>that you</span> <span>have shown me</span>
<span>...<br>
<br>
</span></span>'define chill =
13.12+0.6215*(t-273.15)-11.37*pow((tg1*3.6),0.16)+0.3965*(t-273.15)*pow((tg1*3.6),0.16)'<br>
<br>
</font><font face="Dax"> Date / wind (KPH) / temp (ºC) / windchill
(ºC)<br>
2014-FEB-19-13Z 27.5996 18.8929 18.2662<br>
2014-FEB-19-14Z 31.2976 19.2836 18.6438<br>
2014-FEB-19-15Z 31.2976 19.0446 18.3308<br>
<br>
I still think that with a wind of 30 km/h and a temperature of
18.8 °C, the windchill can not be a 'lower tenths'..</font><br>
<font face="Dax">
<span lang="en"><span>I'm</span> <span>confused,</span> <span>and</span> <span>I have</span> <span>no</span> <span>security</span> <span>...<br>
</span></span><a href="http://www.easysurf.cc/cnver16.htm" target="_blank">http://www.easysurf.cc/cnver16.htm</a><br>
<a href="http://es.easycalculation.com/weather/wind-chill.php" target="_blank">http://es.easycalculation.com/weather/wind-chill.php</a><br>
<br>
Best, <br>
<br>
Leopoldo Alvarez<br>
</font>
</div>
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<br></blockquote></div><br></div>