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<font face="Dax">Hi Willians, </font><font face="Dax"><br>
</font><br>
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<span id="result_box" class="short_text" lang="en"><span
class="hps">Look at</span> <span class="hps">this
webpage-><br>
</span></span><a class="moz-txt-link-freetext" href="http://www.lenntech.com/calculators/wind/wind-chill.htm">http://www.lenntech.com/calculators/wind/wind-chill.htm</a><br>
30 km/h (wind)<br>
18ºC (temperature)<br>
12.1ºC (windchill)<br>
<br>
- - - - - - - - - - -<br>
</font><br>
<font face="Dax">
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<span id="result_box" class="short_text" lang="en"><span
class="hps">In our examples</span> <span class="hps">....<br>
</span></span>I use your formulation...</font><br>
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<span id="result_box" class="short_text" lang="en"><span
class="hps">- [1] I</span> <span class="hps">use</span> your
<span class="hps">formulation </span></span></font><font
face="Dax"><span id="result_box" class="short_text" lang="en"><span
class="hps"><font face="Dax"><span id="result_box"
class="short_text" lang="en"><span class="hps">corrected
(convert KPH to MPH and K to F to input into the
equation)</span></span></font></span></span></font><font
face="Dax"><span id="result_box" class="short_text" lang="en"><span
class="hps"><font face="Dax"><span id="result_box"
class="short_text" lang="en"><span class="hps">
<meta http-equiv="content-type" content="text/html;
charset=ISO-8859-1">
</span></span></font></span></span></font><font face="Dax"><span
id="result_box" class="short_text" lang="en"><span class="hps"><font
face="Dax"><span id="result_box" class="short_text"
lang="en"><span class="hps"></span> </span></font><br>
<br>
</span></span>'far=((9/5)*t)-459.67'<br>
'mph=tg1*2.236936'<br>
'define chill =
35.74+0.6215*far-35.75*pow(mph,0.16)+0.4275*far*pow(mph,0.16)'<br>
'chill2=(chill-32)/1.8'<br>
'd chill2'<br>
</font><br>
<font face="Dax"> Date / wind (MPH) / temp (ºF) / windchill (ºF)<br>
2014-FEB-19-13Z </font><font face="Dax"><font face="Dax">17.1496
</font> </font><font face="Dax"><font face="Dax">66.0072</font>
</font><font face="Dax"><font face="Dax">64.8952<br>
</font>2014-FEB-19-14Z </font><font face="Dax"><font face="Dax">19.4474</font>
</font><font face="Dax"><font face="Dax">66.7105</font> </font><font
face="Dax"><font face="Dax">65.5746<br>
</font>2014-FEB-19-15Z </font><font face="Dax"><font face="Dax">19.4474</font>
</font><font face="Dax"><font face="Dax">66.2803</font> </font><font
face="Dax">65.0114</font><br>
<br>
<br>
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<span id="result_box" class="" lang="en"><span class="hps">- [2]
This is the other</span> <span class="hps">proposal</span> <span
class="hps">that you</span> <span class="hps">have shown me</span>
<span class="hps">...<br>
<br>
</span></span>'define chill =
13.12+0.6215*(t-273.15)-11.37*pow((tg1*3.6),0.16)+0.3965*(t-273.15)*pow((tg1*3.6),0.16)'<br>
<br>
</font><font face="Dax"> Date / wind (KPH) / temp (ºC) / windchill
(ºC)<br>
2014-FEB-19-13Z 27.5996 18.8929 18.2662<br>
2014-FEB-19-14Z 31.2976 19.2836 18.6438<br>
2014-FEB-19-15Z 31.2976 19.0446 18.3308<br>
<br>
I still think that with a wind of 30 km/h and a temperature of
18.8 °C, the windchill can not be a 'lower tenths'..</font><br>
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<span id="result_box" class="short_text" lang="en"><span
class="hps">I'm</span> <span class="hps">confused,</span> <span
class="hps">and</span> <span class="hps">I have</span> <span
class="hps">no</span> <span class="hps">security</span> <span
class="hps">...<br>
</span></span><a class="moz-txt-link-freetext" href="http://www.easysurf.cc/cnver16.htm">http://www.easysurf.cc/cnver16.htm</a><br>
<a class="moz-txt-link-freetext" href="http://es.easycalculation.com/weather/wind-chill.php">http://es.easycalculation.com/weather/wind-chill.php</a><br>
<br>
Best, <br>
<br>
Leopoldo Alvarez<br>
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