Grads Lat Lon problem

[Oliver König]

On Thursday 21 July 2005 20:57, Dan Schwarzkopf wrote:
> set lon -20 30
> set lat xx yy
> define newvar = water_surf_temp
> d newvar

Hello Dan, Stephen and GrADS-Users,
Dan, what's the point in your suggestion? All you suggest is to define a new
variable. However, I found a fix for the problem:

'set lat 30 68'

*Plot Water surface temperature west of 0°
'set lon 345 402'
'd water_surf_temp'

*Plot Water surface temperature east of 0°
'set lon -15 42'
'd water_surf_temp'

Regards

--
Oliver König

>Hello,
>I am loading DODS data which contains sea surface temperature for the entire
>globe.
>
>ga-> q dims
>Default file number is: 1
>X is varying   Lon = 0 to 359.9   X = 1 to 3600
>Y is varying   Lat = -70 to 79.9977   Y = 1 to 1501
>Z is fixed     Lev = 0  Z = 1
>T is fixed     Time = 03Z21JUL2005  T = 1
>
>When I display the the entire data with: 'd water_surf_temp' then grads plots
>the world map with the data starting at 0 degrees longitude (London) on the
>left and stopping at 360 degress longitude.
>
>I want to plot a map for the entire Europe (including the parts of Europe
that
>lie west of 0 degrees longitude (London). Therefore I tried:
>
>set lon -20 30
>or
>set lon 340 -30
>
>Grads either doesn't plot anything at all or it plots only the part east of
>London. How can I solve the problem? Many thanks for your help.
>
>--
>Oliver König