Daily precip average

[Daniel de Castro Victoria]

Don't you just hate leap years :)

Michael, thanks for the heads up... I'll export the data and use some
other software for the average

Cheers

Daniel

Michael Timlin wrote:
> Since you have 7*365+1 days, I'm assuming you have data that includes
> the leap day in 1988.  The calculation you show below does not
> account for the extra day in 1988.  You will actually be averaging as
> follows:
>
> For t=1, averages 1jan85, 86, 87, 88 with 31dec88, 89, 90, 91.
> For t=2, averages 2jan85, 86, 87, 88 with 1jan89, 90, 91.
> For t=3, averages 3jan85, 86, 87, 88 with 2jan89, 90, 91.
> ...
> For t=59, averages 28feb85, 86, 87, 88 with 27feb89, 90, 91.
> For t=60, averages 1mar85, 86, 87, with 29feb88 and with 28feb89, 90, 91.
> For t=61, averages 2mar85, 86, 87, with 1mar88, 89, 90, 91.
> For t=62, averages 3mar85, 86, 87, with 2mar88, 89, 90, 91.
> For t=63, averages 4mar85, 86, 87, with 3mar88, 89, 90, 91.
> ...
> For t=365, averages 31dec85, 86, 87, with 30dec88, 89, 90, 91.
>
> As far as I know you can't do this within grads unless you omit the
> values for 29feb1988.
>
> Mike Timlin
> timlin at atmos.uiuc.edu
>
>
>
>> Hi all,
>>
>> I have a file with daily precip for 2556 days for a watershed (1jan1985
>> to 31dec1991). What I'm trying to do is a daily precipitation average,
>> that is, 1jan average precip (85,86,87,88,89,90,91), 2jan average precip
>> and so forth, for an entire year.
>>
>> So far I have been using these commands:
>>
>> set x 1
>> set y 1
>> set t 1 365
>> d tloop(ave(aave(ppt,x=1,x=33,y=1,y=31),t+0,t=2556,365))
>>
>> The display command works fine but I'm not sure I'm doing the right
>> calculations. Could someone confirm if I'm on the right track? Or am I
>> totally wrong?
>>
>> Thanks a bunch
>>
>> Daniel
>>
>>
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>
>
>


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