<div dir="ltr"><div>Leopoldo,<br><br></div>Unfortunately, you&#39;ll need to convert your KPH to MPH and C to F to input into the equation, and then convert the windchill temp back to C afterwards. It&#39;s a little tedious, but the equation only works with F and MPH. The whole regression equation would have to be changed to work with KPH and C by default.<br>
</div><div class="gmail_extra"><br clear="all"><div><div dir="ltr"><b>William (L.B.) LaForce</b><div>Meteorologist</div><div>Central Michigan University &#39;13<br></div><div><a href="http://www.tornadoinsanity.com" target="_blank">www.tornadoinsanity.com</a></div>
</div></div>
<br><br><div class="gmail_quote">On Sun, Feb 23, 2014 at 2:30 PM, Leopoldo Alvarez <span dir="ltr">&lt;<a href="mailto:lap.bolsa@gmail.com" target="_blank">lap.bolsa@gmail.com</a>&gt;</span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">

  

    
  
  <div bgcolor="#FFFFFF" text="#000000">
    <font face="Dax">Hi Willians,<br>
    </font><br>
    <font face="Dax">
      
      <span lang="en"><span>- [1] I
          used</span> <span>your </span><span></span>
        <span>formulation</span> <span>but</span>
        <span>using</span> <span>degrees
          Celsius (ºC) and</span> KPH...</span></font>
    
    <span lang="en"><span>
        I</span> <span>don´t know if</span> <span>it is</span> <span>valid...</span></span><br>
    
    <span lang="en"><span>Now</span>
      <span></span><span>temperature is more
        low...mmmh<br>
      </span></span><font face="Dax"><br>
      &#39;define chill =
35.74+0.6215*(t-273.15)-35.75*pow((tg1*3.6),0.16)+0.4275*(t-273.15)*pow((tg1*3.6),0.16))&#39;<br>
    </font><font face="Dax"><br>
       Date / wind (KPH) / temp (ºC) / windchill (ºC)<br>
      2014-FEB-19-13Z  27.5996  18.8929   0.426981<br>
      2014-FEB-19-14Z  31.2976  19.2836   0.00337819<br>
      2014-FEB-19-15Z  31.2976  19.0446  -0.322477<br>
      <br>
      <br>
    </font>
    
    <span lang="en"><span>-[2]
        In other</span> </span><font face="Dax"><span lang="en"><span> </span><span></span>
        <span>formulation </span></span></font><span lang="en"><span></span><span>the difference</span> <span>was less</span>
      <span>...</span></span><br>
    <a href="http://www.wrfems.info/viewtopic.php?f=6&amp;t=742" target="_blank">http://www.wrfems.info/viewtopic.php?f=6&amp;t=742</a><br>
    <font face="Dax">- &#39;tg2&#39; is wind variable (KPH)</font><br>
    <span lang="en"><span><font face="Dax">&#39;define wis=pow((tg2),0.16)&#39;<br>
          &#39;define windchill = 13.112 + 0.6215*(t-273.15) - 11.37*wis +
          0.3965*(t-273.15)*wis&#39;<br>
          &#39;d windchill&#39;<br>
          <br>
          here </font></span></span><span lang="en"><span>I find</span> <span>little difference, </span></span> <span lang="en"><span>I
        wonder...<br>
        <br>
      </span></span> Date / wind (KPH) / temp (ºC) / windchill (ºC)<br>
    2014-FEB-19-13Z  27.5996  18.8929  18.2582<br>
    2014-FEB-19-14Z  31.2976  19.2836  18.6358<br>
    2014-FEB-19-15Z  31.2976  19.0446  18.3228<br>
    <br>
    
    <span lang="en"><span>If</span>
      <span>your</span> <span>test this web
        with my data</span></span> [2], is similar windchill..<br>
    <a href="http://www.csgnetwork.com/windchillcalc.html" target="_blank">http://www.csgnetwork.com/windchillcalc.html</a><br>
    <br>
    Best, <br>
    <br>
    Leopoldo<br>
  </div>

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<br></blockquote></div><br></div>