<html><head><style type='text/css'>p { margin: 0; }</style></head><body><div style='font-family: arial,helvetica,sans-serif; font-size: 12pt; color: #000000'>First you need to find the height of a column of water of area 1 m^2 and mass 1 kg. Since the density of liquid water is ~1000 kg/m^3, the height of the column must be 0.001 m, or 1 mm. Numerically, the "conversion" from kg/m^2 to mm of liquid water is 1. To convert the precip rate to mm/day, multiply by 86400. To get it in mm/month, multiply by the number of days in the month you're interested in.<br><br><hr id="zwchr"><b>From: </b>"asmat ullah" <asmat-786@hotmail.com><br><b>To: </b>gradsusr@gradsusr.org<br><b>Sent: </b>Tuesday, November 26, 2013 4:12:02 AM<br><b>Subject: </b>[gradsusr] need help regarding time conversion<br><br>
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<div dir="ltr"><pre style="word-wrap: break-word; white-space: pre-wrap;">pr_1_transformed_regrid, Season_1_per_year
VARIABLE : Average Precipitation [ x=60.75:74.3@Average y=23.3:30.25@Average] (kg m-2 s-1) every Dec ((kg m-2 s-1))
SUBSET : 22 points (TIME)
CALENDAR : NOLEAP
16-DEC-1979 / 1: 2.985E-07
16-DEC-1980 / 2: 1.188E-06
16-DEC-1981 / 3: 3.238E-06
16-DEC-1982 / 4: 7.722E-07</pre><pre style="word-wrap: break-word; white-space: pre-wrap;">i have these values of GFDL CM2.0, for exampal a value <span style="font-family: Calibri, sans-serif; font-size: 12pt;">2.985E-07, as this value is in </span><span style="font-family: Calibri, sans-serif; font-size: 12pt;">(kg m-2 s-1), i want to convert in mm/month so please help me in this regard.</span></pre> </div>
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