Multiply by 3600.<div><br></div><div>kg/m^2 is just a mass per unit area. If you divide by the density, you get meters. But since the density of liquid water at 0 C is 1000 kg/m^3, then kg/m^2/s is equivalent to mm/s.</div>
<div><br></div><div>Jeff Duda<br><br><div class="gmail_quote">On Wed, Jul 24, 2013 at 3:49 PM, leonardo <span dir="ltr"><<a href="mailto:leoclarke@yahoo.com" target="_blank">leoclarke@yahoo.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div><div style="font-size:10pt;font-family:arial,helvetica,sans-serif"><div>Dear GRADS Users</div><div><br></div><div style="font-style:normal;font-size:13.3333px;background-color:transparent;font-family:arial,helvetica,sans-serif">
This is not a GRADS question but I hope someone can help.</div><div style="font-style:normal;font-size:13.3333px;background-color:transparent;font-family:arial,helvetica,sans-serif"><br></div><div style="font-style:normal;font-size:13.3333px;background-color:transparent;font-family:arial,helvetica,sans-serif">
I have a data set with precipitation flux (kg m-2 s-1). Does</div><div style="font-style:normal;font-size:13.3333px;background-color:transparent;font-family:arial,helvetica,sans-serif">anyone know how can I convert to precipitation rate in (mm d-1)?</div>
<div style="font-style:normal;font-size:13.3333px;background-color:transparent;font-family:arial,helvetica,sans-serif"><br></div><div style="font-style:normal;font-size:13.3333px;background-color:transparent;font-family:arial,helvetica,sans-serif">
Thanks</div><div style="font-style:normal;font-size:13.3333px;background-color:transparent;font-family:arial,helvetica,sans-serif">LC</div></div></div><br>_______________________________________________<br>
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<br></blockquote></div><br><br clear="all"><div><br></div>-- <br>Jeff Duda<br>Graduate research assistant<br>University of Oklahoma School of Meteorology<br>Center for Analysis and Prediction of Storms<br>
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