<html><head><style type='text/css'>p { margin: 0; }</style></head><body><div style='font-family: arial,helvetica,sans-serif; font-size: 12pt; color: #000000'>Dear Mohsen,<div><br></div><div>At a given point, temperature advection is that portion of the local temperature tendency due to the wind blowing across the isotherms. The units can be determined from the equation:</div><div><br></div><div>Tadv = -(U*dT/dx + V*dT/dy)</div><div><br></div><div>Using the first term, U has dimensions of (length/time) and dT/dx has dimensions of (temperature/length), multiplication gives units of (temperature/time) which is what K/day is.</div><div><br></div><div>Eric<br><br><hr id="zwchr"><b>From: </b>"Mohsen Soltani" <soltani.clima@gmail.com><br><b>To: </b>"GrADS Users Forum" <gradsusr@gradsusr.org><br><b>Sent: </b>Saturday, May 25, 2013 11:59:33 AM<br><b>Subject: </b>Re: [gradsusr] Temperature Advection<br><br>Dear Eric,<br><br>Thank you very much for your help. The attached in the new map (warm<br>air advection - k/day) based on the new display.<br>But, you know, the unit of the map (K/day) is a little bizarre to me!!<br>Would you please explain it to me in a few words?<br>FYI: the unit of variables are in terms of: air temperature: K, and<br>U&V wind components: m/s.<br><br>Thanks again,<br><br>Mohsen<br><br>-- <br>--<br>some are weather-wise some are otherwise!<br>--<br>Best Wishes,<br>(Mr.) Mohsen Soltani<br>Climatology Grad Student (M.Sc.),<br>Faculty of Geography, University of Tehran, Tehran, Iran<br>Tel: (+98) 9119772934<br>e-mail: soltani.clima@gmail.com<br><br>_______________________________________________<br>gradsusr mailing list<br>gradsusr@gradsusr.org<br>http://gradsusr.org/mailman/listinfo/gradsusr<br></div></div></body></html>