<div dir="ltr"><div class="gmail_default" style="font-family:arial,helvetica,sans-serif"><p class="" style="margin-bottom:0.0001pt"><span style="font-family:Arial,sans-serif">Hello
Eric,</span></p>
<p class="" style="margin-bottom:0.0001pt"><span style="font-family:Arial,sans-serif">Thanks
for your email. Actually, I rechecked the plots and I have to say
that the annual plot is real/correct. The unit is in terms
of millimeter (mm).</span></p>
<p class="" style="margin-bottom:0.0001pt"><span style="font-family:Arial,sans-serif">FYI: I
used the daily precipitation data complied by APHRODITE's water resources with
a resolution 0.25</span><span style="font-family:Arial,sans-serif"> x</span><span style="font-family:Arial,sans-serif"> 0.25 degrees grid over the Middle East including
Iran.</span></p>
<p class="" style="margin-bottom:0.0001pt"><span style="font-family:Arial,sans-serif">Mohsen</span></p></div></div><div class="gmail_extra"><br clear="all"><div><div dir="ltr"><span><span style="font-size:11.0pt;line-height:115%;font-family:"Calibri","sans-serif";color:#888888"></span></span><span><span dir="RTL" style="font-size:11.0pt;line-height:115%;font-family:"Arial","sans-serif";color:#888888" lang="AR-SA"><span></span></span></span>--<div>
some are weather-wise some are otherwise!</div><div>--<br>Best Wishes, <br>(Mr.) Mohsen Soltani<br>Climatology Grad Student (M.Sc.),<br>Faculty of Geography, University of Tehran, Tehran, Iran<br>
Tel: (+98) 9119772934<br>e-mail: <a href="mailto:soltani.clima@gmail.com" target="_blank">soltani.clima@gmail.com</a><br></div></div></div>
<br><br><div class="gmail_quote">On Thu, May 16, 2013 at 6:50 PM, Eric Altshuler <span dir="ltr"><<a href="mailto:ela@cola.iges.org" target="_blank">ela@cola.iges.org</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div><div style="font-size:12pt;font-family:arial,helvetica,sans-serif">Dear Mohsen,<div><br></div><div>I was looking at the two precip plots you made, and I noticed the values in the April-June plot are about 3 times larger than those in the annual plot (for the same period). Which plot has the correct values and what are the units?</div>
<div><br></div><div>Thanks</div><div><br><div><span name="x"></span>Eric L. Altshuler<br>Research Scientist<br>Center for Ocean-Land-Atmosphere Studies<br>4041 Powder Mill Road, Suite 302<br>Calverton, MD 20705-3106<br>USA<br>
<br>E-mail: <a href="mailto:ela@cola.iges.org" target="_blank">ela@cola.iges.org</a><br>Phone: (301) 902-1257<br>Fax: (301) 595-9793<span name="x"></span><br></div><br><hr><b>From: </b>"Mohsen Soltani" <<a href="mailto:soltani.clima@gmail.com" target="_blank">soltani.clima@gmail.com</a>><br>
<b>To: </b>"GrADS Users Forum" <<a href="mailto:gradsusr@gradsusr.org" target="_blank">gradsusr@gradsusr.org</a>><br><b>Sent: </b>Wednesday, May 15, 2013 1:24:56 PM<br><b>Subject: </b>Re: [gradsusr] calculating the trend for summer seasons<br>
<br>hi,<br><br>You may also use the following example script to plot time-series for<br>your precipitation data.<br><br>t1='1june2012'<br>t2='30august2012'<br> 'set time 't1' 't2<br> 'set gxout bar'<br>
'set bargap 25'<br> 'set barbase 0'<br> 'set vrange 2''set ylint 2'<br> 'set ccolor 4'<br> 'd precip' (or your var name)<br><br>This will plot a bar-chart for 3 months of the summer in the year 2012<br>
only. The attached plot is just as an output example.<br><br>Mohsen<br><br>On 5/15/13, Luis Blacutt <<a href="mailto:luis.blacutt@gmail.com" target="_blank">luis.blacutt@gmail.com</a>> wrote:<br>> Hi Gürol,<br>><br>
> You need to know what your variable names are, you will find it by tiping<br>> q file<br>> then you can use simple powerful tools, such as<br>> d ave(variablename,t=initialtime,t=finaltime,timestep)<br>> that in your case might be t=6, t=408, timestep=12, that will calculate the<br>
> average for june for the whole period (1979-2012), and so on<br>><br>> Best regards<br>> Luis<br>><br>><br>> On Wed, May 15, 2013 at 10:53 AM, Gürol Çerçi <<a href="mailto:cercig@gmail.com" target="_blank">cercig@gmail.com</a>> wrote:<br>
><br>>> Hello,<br>>><br>>> I have a monthly precipitation data set, 3 dimensional (lat, lon, time)<br>>> in<br>>> netcdf format.<br>>><br>>> For a specific grid point, I want to calculate the linear trend between<br>
>> 1979-2012 for total summer values (June+July+August).<br>>><br>>> Any tips to do that as the easiest way? (I have already the script to<br>>> calculate the linear trend).<br>>><br>>> For example:<br>
>> set lat 10<br>>> set lon 160<br>>> set t something<br>>> then what to write?<br>>><br>>> Thanks...<br>>> --<br>>> Gürol Çerçi<br>>> Meteorological Engineer<br>>><br>
>> _______________________________________________<br>>> gradsusr mailing list<br>>> <a href="mailto:gradsusr@gradsusr.org" target="_blank">gradsusr@gradsusr.org</a><br>>> <a href="http://gradsusr.org/mailman/listinfo/gradsusr" target="_blank">http://gradsusr.org/mailman/listinfo/gradsusr</a><br>
>><br>>><br>><br><br><br>-- <br>--<br>some are weather-wise some are otherwise!<br>--<br>Best Wishes,<br>(Mr.) Mohsen Soltani<br>Climatology Grad Student (M.Sc.),<br>Faculty of Geography, University of Tehran, Tehran, Iran<br>
Tel: (+98) 9119772934<br>e-mail: <a href="mailto:soltani.clima@gmail.com" target="_blank">soltani.clima@gmail.com</a><br><br>_______________________________________________<br>gradsusr mailing list<br><a href="mailto:gradsusr@gradsusr.org" target="_blank">gradsusr@gradsusr.org</a><br>
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<br></blockquote></div><br></div>