change your last line to <div>SECOND_DERIVATIVE = cdiff(dTX,x)/dx</div><div><br></div><div>Although, there is a problem with representing dx using cdiff(lon,x). Since the longitude change along a parallel is a function of longitude, you need to account for that to get a truly accurate second derivative in space. This will be especially problematic near the poles.</div>
<div><br></div><div>Jeff Duda<br><br><div class="gmail_quote">On Mon, Oct 1, 2012 at 2:02 PM, one weather <span dir="ltr"><<a href="mailto:oneweather@gmail.com" target="_blank">oneweather@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">Hello!!<br>
<br>
I would like to draw the second derivative of the temperature. Is<br>
correct if I do this?<br>
<br>
>define dTX=cdiff(tmp2m,x)<br>
>define dx=cdiff(lon,x)<br>
>define SECOND_DERIVATIVE=(dTx/dx)/dx<br>
<br>
Thank you so much!!<br>
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</blockquote></div><br><br clear="all"><div><br></div>-- <br>Jeff Duda<br>Graduate research assistant<br>University of Oklahoma School of Meteorology<br>Center for Analysis and Prediction of Storms<br><br>
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