Thanks. I think defining Iave in a different line is taking the value when t=1.<br>Thus, this would perhaps be the answer... any comments!<br>
<div>'sdfopen <a href="http://temp.2000.nc/" target="_blank" onclick="return top.js.OpenExtLink(window,event,this)">temp.2000.nc</a>'<br>'set lon 40 200'; 'set z 1 12'; 'set lat 0'; 'set t 1'
<br>'define tave=ave(ave(temp,time=20mar,time=10jun),lat=-5,lat=5)'<br>*'define lave=ave(temp, lat=-5,lat=5)'<br>'define aa=ave(ave(temp,lat=-5,lat=5)-tave,time=20mar,time=25mar)'<br>'d aa'
</div><br><br><br><br><div><span class="gmail_quote">On 3/14/07, <b class="gmail_sendername">Eduardo Agosta Scarel</b> <<a href="mailto:eduardo.agosta@gmail.com">eduardo.agosta@gmail.com</a>> wrote:</span><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<div>Try with the following, perhaps it works.</div>
<div> </div>
<div> </div>
<div>'sdfopen <a href="http://temp.2000.nc/" target="_blank" onclick="return top.js.OpenExtLink(window,event,this)">temp.2000.nc</a>'<br>'set lon 40 200'; 'set z 1 12'; 'set lat 0'; 'set t 1'
<br>'define tave=ave(ave(temp,time=20mar,time=10jun),lat=-5,lat=5)'</div>
<div>'define lave=ave(temp, lat=-5,lat=5)'<br>'define aa=(ave(lave-tave,time=20mar,time=25mar))'<br>'d aa'</div>
<div> </div>
<div>It may estimate the band-latitude average and then the time anomaly.</div>
<div>Good luck!</div><span class="sg">
<div>Eduardo.</div>
</span></blockquote></div><br><br clear="all"><br>-- <br>John Guhin