[gradsusr] Not standard variable name

[iri]

Hi all !

I work with the model "AROME" by Météo-France.
I download a grib2 file from
https://mf-models-on-aws.org/#arome-france/v2/2019-07-06/06/GP/pv/ to
get PVU (1.5 and 2).

$ wgrib2 arome-france_20190706_06_GP_pv_17h.grib2
1:0:d=2019070606:GP:PV=2000 (Km^2/kg/s) surface:17 hour fcst:
2:221788:d=2019070606:GP:PV=1500 (Km^2/kg/s) surface:17 hour fcst:

$ g2ctl file.grib2 > pvu.ctl

ga-> open pvu.ctl

ga-> q file
File 1 : arome-france_20190706_06_GP_pv_17h.grib2
  Descriptor: pvu.ctl
  Binary: arome-france_20190706_06_GP_pv_17h.grib2
  Type = Gridded
  Xsize = 801  Ysize = 601  Zsize = 1  Tsize = 1  Esize = 1
  Number of Variables = 2
     gp2e+09pv  0  0,3,4  ** PV=2000 (Km^2/kg/s) surface Geopotential
[m^2/s^2]
     gp1p5e+09pv  0  0,3,4  ** PV=1500 (Km^2/kg/s) surface Geopotential
[m^2/s^2]

ga-> d gp2e+09pv
Syntax Error:  Invalid Operand
  'gp2e' not a variable or function name
  Error ocurred at column 1
DISPLAY error:  Invalid expression
  Expression = gp2e+09pv

I tried with wgrib2 -set_var, it changes only GP to HGT and the final
name in ctl becomes hgt2e+09pv
It is a logical result.

I tested with alt_g2ctl and -short option. In this case :

ga-> open pvu2.ctl
Scanning description file:  pvu2.ctl
Data file arome-france_20190706_06_GP_pv_17h.grib2 is open as file 1
LON set to -8 12
LAT set to 38 53
LEV set to 1 1
Time values set: 2019:7:6:23 2019:7:6:23
E set to 1 1

ga-> q file
File 1 : arome-france_20190706_06_GP_pv_17h.grib2
  Descriptor: pvu2.ctl
  Binary: arome-france_20190706_06_GP_pv_17h.grib2
  Type = Gridded
  Xsize = 801  Ysize = 601  Zsize = 1  Tsize = 1  Esize = 1
  Number of Variables = 2
     v1  0  0  "GP:PV=1500 (Km^2/kg/s) surface"
     v2  0  0  "GP:PV=2000 (Km^2/kg/s) surface"

ga-> d v1
Cannot contour grid - all undefined values

How can i rename gp1p5e+09pv to gp1p5e by example ?

Thank you for your help in advance.

Stephane Iri
InC + PE13
Marseille, France