[gradsusr] define new field

[Rabah Hachelaf]

Hi Stephen,

Thank yo for reply but when using the second way :
i have this error :

ga-> define newfld=const(vgrd10m,1,-a)
Syntax Error:  Invalid dimension expression
  Expecting +/-/= operator, found 1
  Variable name = const
  Error ocurred at column 1
DEFINE error:  Invalid expression.

I am using grads2.1 .


2014-07-17 15:55 GMT-04:00 Stephen McMillan <smcmillan at planalytics.com>:

> Rabah,
> If you have opengrads, you could use "if" function, for example:
> 'define newfld=if(var,<,1000,1,-u)'  where var is an available variable
> whose values are < 1000
>
> Otherwise, you could use const, for example:
> 'define newfld=const(var,1,-a)'  where var is an available variable
>
> Hope above helps.
> Stephen McMillan
>
>
> On Thu, Jul 17, 2014 at 3:07 PM, Rabah Hachelaf <r.hachelaf at gmail.com>
> wrote:
>
>> Hello all,
>>
>> How can i define a new field (Xsize,Ysize) containing constant value (1
>> for exemple) in GRADS.
>>
>> Thanks.
>>
>> --
>> ------------------------------
>> Cordialement,
>> Best regards,
>> Rabah Hachelaf
>>
>>
>>
>> _______________________________________________
>> gradsusr mailing list
>> gradsusr at gradsusr.org
>> http://gradsusr.org/mailman/listinfo/gradsusr
>>
>>
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-- 
------------------------------
Cordialement,
Best regards,
Rabah Hachelaf
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