[gradsusr] Thanks Jeff. cdiff function

[Adrian Scherzinger]

Jeff,
thanks a lot for your help. It works now with the "define solution" for 
my purposes.
Best regards
Adrian

___________________________
Adrian Scherzinger
Stv. Leiter Wetterprognosen

Genossenschaft METEOTEST
Fabrikstrasse 14, CH-3012 Bern
Tel +41 (0)31 307 26 26
Fax +41 (0)31 307 26 10
adrian.scherzinger at meteotest.ch
http://www.meteotest.ch

********************************************************************
0900 57 61 52 (CHF 3.13/Min) im direkten Dialog mit dem Prognostiker
METEOFON - das persönliche Wettertelefon von METEOTEST (05-18 Uhr)
********************************************************************


On 20.10.2010 17:40, Jeffrey Duda wrote:
> Adrain,
> Indeed, the CDIFF function won't help you here, but it sounds like you 
> have answered your own question.  All you need to do is (quoted from 
> your message): "(rain at t=x)-(rain at t=x-1)" and almost in that 
> exact syntax.  Whatever your "rain" variable is called (I'll call it 
> "rain" in this example), just do 'd rain(t=x) - rain(t=x-1)', or if 
> you want to do this over a range of values, do either
>
> 'set t t1 t2'
> 'd tloop(rain-rain(t-1))'
>
> OR
>
> 'set t t1 t2'
> 'define rainvariable = rain-rain(t-1)'
> 'd rainvariable'
>
> That should work.
>
> Jeff Duda
>
> On Wed, Oct 20, 2010 at 8:18 AM, Adrian Scherzinger 
> <adrian.scherzinger at meteotest.ch 
> <mailto:adrian.scherzinger at meteotest.ch>> wrote:
>
>      Hi
>     I am looking for a function similar to cdiff, BUT instead of
>     "The result value at each grid point is the value at the grid
>     point plus
>     one minus the value at the grid point minus one."
>     i need a funktion that calculates:
>     "The result value at each grid point is the value at the grid point
>     minus the value at the grid point minus one."
>
>     This is my problem:
>     Each timestep of my mm5 precipitation data set contains the
>     integral of
>     the precipitation since t=1. I want to plot a bar graph with the
>     precipitation of each hour (not the integral). If I want to get the
>     value only at time X, I need to calculate (rain at t=x)-(rain at
>     t=x-1).
>     cdiff(rain,t) is not the solution.
>
>     Thanks for your help
>     Adrian
>
>     --
>     ___________________________
>     Adrian Scherzinger
>     Stv. Leiter Wetterprognosen
>
>     Genossenschaft METEOTEST
>     Fabrikstrasse 14, CH-3012 Bern
>     Tel +41 (0)31 307 26 26
>     Fax +41 (0)31 307 26 10
>     adrian.scherzinger at meteotest.ch
>     <mailto:adrian.scherzinger at meteotest.ch>
>     http://www.meteotest.ch
>
>     ********************************************************************
>     0900 57 61 52 (CHF 3.13/Min) im direkten Dialog mit dem Prognostiker
>     METEOFON - das persönliche Wettertelefon von METEOTEST (05-18 Uhr)
>     ********************************************************************
>
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>
>
>
>
> -- 
> Jeff Duda
> Iowa State University
> Meteorology Graduate Student
> 3134 Agronomy Hall
> www.meteor.iastate.edu/~jdduda <http://www.meteor.iastate.edu/%7Ejdduda>
>
>
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