Defining Leap years

[Mary Jo Nath]

You could try using the math function in the script.

rc = math_mod(num1,num2);

      num1       any number
      num2       any number not equal to zero
      rc         the integer part of the remainder when num1 is divided
by num2

num1 = year
num2 = 4
rc = 0 if year is evenly divisible by 4.

Katherin Kullgren wrote:
> Hello there,
> I am wondering if anyone could assist me.  I am trying to write daily data
> into one file from many year files.  I am trying to use a (if then)
> statement to define the files that contain a leap year.  Something like this
>
> year = 1950
> endday = 365
> leap = 366
>
>
>
> while (pfile <= 50)
> ..
> ..
> ..
> if (year/4 = real(year)/4.0) then
> while (t <= endday)
> ..
> ..
> ..
> endwhile
> else
> while (t <= leap)
> ..
> ..
> ..
> endwhile
> endif
>
> pfile = pfile + 1
> endwhile
>
> but the format is not the same as fortran.  It does not understand
> real(year).  Can anyone make a suggestion on how to define the leap year files?
> Thanks for your help in advance.
> Katherin
>
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