R: [GRADSUSR] compare 4 timeseries

[bernd.becker at METOFFICE.GOV.UK]

Mandelli,
this all makes perfect sense:

The data has an arbitrarily set year 23648.
The four file contain the 6 hourly climatology,
each holding one of the 4 daily 6 hourly assimilation cycles.

A single point in this example is as good anything here.

The question is:

how do you get the maximum/minimum value from a set of 4 numbers,
each from a different file at all x,y,z, and days?

Thanks.

Brute force comparison using scripting may be the only way forward,
but I am still hopeful, because grads has proved to be so very
resourceful.

Cheers,
Bernd.


On Fri, 2007-08-03 at 17:37 +0200, Mandelli Alessandro wrote:
> > -----Messaggio originale-----
> > Da: GRADSUSR at LIST.CINECA.IT [mailto:GRADSUSR at LIST.CINECA.IT] Per conto di
> > bernd.becker at METOFFICE.GOV.UK
> > Inviato: venerdì 3 agosto 2007 17.17
> > A: GRADSUSR at LIST.CINECA.IT
> > Oggetto: [GRADSUSR] compare 4 timeseries
>
>
> > define t=tloop(min(tmean.62,tmean.63,tmean.64,tmean.66))
>
> Are you sure about 66? Maybe it's a typo, maybe not.... 62, 63, 64, 65?
>
> > T is varying   Time = 00Z01JAN25655 to 00Z22DEC25655  T = 1 to 356
>
> The time series is 23648 years ahead of now. Does it sound ok for you?
>
> And if
> X is fixed     Lon = -97  X = -96
> Y is fixed     Lat = 33  Y = 124
> Z is fixed     Lev = 1  Z = 1
>
> This looks like a single point in space. Does it sound ok for you?
--
Bernd Becker   The Monthly Outlook
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